Mathematics carries the highest weight in AISSEE — 150 of 300 marks in Class 6 and 200 of 400 marks in Class 9 — and it is also a key section of the RMS CET. Practise these 10 MCQs on Natural Numbers and Operations on Numbers, then check your answers and step-by-step solutions in the answer key at the end.
Quick facts: AISSEE 2027 will be held on Sunday, 31 January 2027. There is no negative marking, so attempt every question. Online applications are open until 2 December 2026 on exams.nta.nic.in/sainik-school-society.
Practice Questions
Q1. What is the place value of the digit 4 at position 4 (from left) in 5,454,266?
(A) 40,000
(B) 400
(C) 4
(D) 4,000
Q2. What is the successor of 77108?
(A) 77107
(B) 77118
(C) 77108
(D) 77109
Q3. What is the difference between the largest and smallest 4-digit numbers formed using the digits 7, 6, 3, 1 (each once)?
(A) 6264
(B) 6273
(C) 6291
(D) 6255
Q4. What is the smallest natural number?
(A) 0
(B) −1
(C) 1
(D) 2
Q5. Find the sum of the first 100 natural numbers.
(A) 10000
(B) 5050
(C) 10100
(D) 4950
Q6. What is the place value of the digit 6 at position 1 (from left) in 6,893,648?
(A) 60,000,000
(B) 600,000
(C) 6
(D) 6,000,000
Q7. What is the successor of 28045?
(A) 28046
(B) 28044
(C) 28055
(D) 28045
Q8. What is the difference between the largest and smallest 4-digit numbers formed using the digits 9, 3, 0, 1 (each once)?
(A) 8244
(B) 8253
(C) 8271
(D) 8262
Q9. What is the sum of the first 20 natural numbers?
(A) 200
(B) 210
(C) 190
(D) 420
Q10. Find the sum of the first 30 natural numbers.
(A) 900
(B) 465
(C) 930
(D) 435
Answer Key with Explanations
(D) 4,000 — The digit is in the thousands place, so its place value is 4,000.
(D) 77109 — The successor is one more: 77109.
(A) 6264 — Largest = 7631, smallest = 1367; difference = 6264.
(C) 1 — Natural numbers start from 1.
(B) 5050 — Sum = n(n+1)/2 = 100×101/2 = 5050.
(D) 6,000,000 — The digit is in the ten lakhs (millions) place, so its place value is 6,000,000.
(A) 28046 — The successor is one more: 28046.
(C) 8271 — Largest = 9310, smallest = 1039; difference = 8271.
(B) 210 — Sum = n(n+1)/2 = 20×21/2 = 210.
(B) 465 — Sum = n(n+1)/2 = 30×31/2 = 465.
How did you score?
9–10 correct: excellent — move on to a full-length mock test. 6–8: good — revise the explanations of the questions you missed. Below 6: study this topic again from your NCERT book and retry these questions after two days.
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