Mathematics carries the highest weight in AISSEE — 150 of 300 marks in Class 6 and 200 of 400 marks in Class 9 — and it is also a key section of the RMS CET. Practise these 10 MCQs on Compound Interest, then check your answers and step-by-step solutions in the answer key at the end.
Quick facts: AISSEE 2027 will be held on Sunday, 31 January 2027. There is no negative marking, so attempt every question. Online applications are open until 2 December 2026 on exams.nta.nic.in/sainik-school-society.
Practice Questions
Q1. Find the compound interest on ₹1000 at 10% per annum for 2 years, compounded annually.
(A) ₹210
(B) ₹200
(C) ₹1210
(D) ₹310
Q2. What amount will ₹10000 become in 2 years at 10% per annum compound interest?
(A) ₹12000
(B) ₹2100
(C) ₹12200
(D) ₹12100
Q3. What is the difference between compound interest and simple interest on ₹1000 for 2 years at 5% per annum?
(A) ₹4
(B) ₹50
(C) ₹7
(D) ₹2.50
Q4. The population of a town is 20,000. It increases by 10% every year. What will it be after 2 years?
(A) 24,000
(B) 24,200
(C) 24,400
(D) 22,000
Q5. Find the compound interest on ₹5000 at 10% per annum for 2 years, compounded annually.
(A) ₹1050
(B) ₹1000
(C) ₹6050
(D) ₹1550
Q6. What amount will ₹4000 become in 2 years at 20% per annum compound interest?
(A) ₹5600
(B) ₹1760
(C) ₹5760
(D) ₹5860
Q7. What is the difference between compound interest and simple interest on ₹2000 for 2 years at 10% per annum?
(A) ₹40
(B) ₹20
(C) ₹200
(D) ₹25
Q8. The population of a town is 20,000. It increases by 5% every year. What will it be after 2 years?
(A) 22,000
(B) 22,250
(C) 22,050
(D) 21,000
Q9. Find the compound interest on ₹10000 at 20% per annum for 2 years, compounded annually.
(A) ₹4000
(B) ₹14400
(C) ₹6400
(D) ₹4400
Q10. What amount will ₹8000 become in 2 years at 10% per annum compound interest?
(A) ₹9600
(B) ₹1680
(C) ₹9680
(D) ₹9780
Answer Key with Explanations
(A) ₹210 — A = 1000(1 + 10/100)² = ₹1210; CI = ₹210.
(D) ₹12100 — A = P(1 + R/100)² = 10000×1.1² = ₹12100.
(D) ₹2.50 — For 2 years, CI − SI = P(R/100)² = 1000×(5/100)² = ₹2.50.
(B) 24,200 — Population = 20,000×(1 + 10/100)² = 24,200.
(A) ₹1050 — A = 5000(1 + 10/100)² = ₹6050; CI = ₹1050.
(C) ₹5760 — A = P(1 + R/100)² = 4000×1.2² = ₹5760.
(B) ₹20 — For 2 years, CI − SI = P(R/100)² = 2000×(10/100)² = ₹20.
(C) 22,050 — Population = 20,000×(1 + 5/100)² = 22,050.
(D) ₹4400 — A = 10000(1 + 20/100)² = ₹14400; CI = ₹4400.
(C) ₹9680 — A = P(1 + R/100)² = 8000×1.1² = ₹9680.
How did you score?
9–10 correct: excellent — move on to a full-length mock test. 6–8: good — revise the explanations of the questions you missed. Below 6: study this topic again from your NCERT book and retry these questions after two days.
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